A simple harmonic oscillator consists of a block of mass 2kg attached to a sprin

Question

A simple harmonic oscillator consists of a block of mass 2kg attached to a spring of spring constant 200 N/m. If the speed ofthe block is 40 m/s when the displacement from equilibrium is 3 m,what is the amplitude of the oscillations? Theanswer is 5 m, but I cannot figure out how to get that answer.Please help! A simple harmonic oscillator consists of a block of mass 2kg attached to a spring of spring constant 200 N/m. If the speed ofthe block is 40 m/s when the displacement from equilibrium is 3 m,what is the amplitude of the oscillations? Theanswer is 5 m, but I cannot figure out how to get that answer.Please help!

Explanation / Answer

   Angularfrequency         =   (k/m)                                              =   (200/ 2)                                              =   10   rad/s    speed ofblock      v   =   *(A2   -   x2)    given   v   =   40   m/s    displacement   x   =   3   m    40   =   10 *(A2   -   32)    A2   -   32   =   402/ 102    A2   =   16+ 9    Amplitude   A   =   25                                  =   5   m    A2   =   16+ 9    Amplitude   A   =   25                                  =   5   m

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