How do you figure this question: The speed of a 2 kg object changes form 30 m/s

Question

How do you figure this question: The speed of a 2 kg object changes form 30 m/s to 40 m/sduring a 5 second interval. During this time interval, the velocityof the object changes it's direction by 90 degrees. What is themagnitude of the average total force acting on the object duringthis time interval? Thanks! How do you figure this question: The speed of a 2 kg object changes form 30 m/s to 40 m/sduring a 5 second interval. During this time interval, the velocityof the object changes it's direction by 90 degrees. What is themagnitude of the average total force acting on the object duringthis time interval? Thanks!

Explanation / Answer

mass m = 2 kg time t = 5 s initial velocity   u = 30 i final velocity v = 40 j change in velocity dv = v - u                                 = 40 j - 30 i magnitude of change invelocity = [ 40 ^ 2 +( -30 ) ^ 2 ]                                                = 50 m / s So, accleration a = dv / t                          = 10 m / s^ 2 the magnitude of the average total force acting on theobject during this time interval is F = m a                                                                                                                                          = 20 N time t = 5 s accleration a = dv / t                    =

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