A block is attached to the end of a spring resting on africtionless surface. the

Question

A block is attached to the end of a spring resting on africtionless surface. the springs are to be stretched to the rightby a distance given in the data and released. The blocks will thenproceed to oscillate. The mass is given for each different block,and the forces constant is given for each differnt spring> Rankthe data from gratest to least on the basis of the period ofthe vibratory motion. That is rank the dat on the basis of how longeach will take to go through one complete cycle.... A. 5 N/M, stretched 0.4m, 1 KG B. 5 N/M, stetched 0.2m, 2 kg C. 4 N/M, streched 0.2m, 5 kg D. 1 N/M, stretched 0.5m, 1 kg E. 4 N/M, stretched 0.5m, 4 kg F. 1 N/M, stretched 0.5m, 5 kg A block is attached to the end of a spring resting on africtionless surface. the springs are to be stretched to the rightby a distance given in the data and released. The blocks will thenproceed to oscillate. The mass is given for each different block,and the forces constant is given for each differnt spring> Rankthe data from gratest to least on the basis of the period ofthe vibratory motion. That is rank the dat on the basis of how longeach will take to go through one complete cycle.... A. 5 N/M, stretched 0.4m, 1 KG B. 5 N/M, stetched 0.2m, 2 kg C. 4 N/M, streched 0.2m, 5 kg D. 1 N/M, stretched 0.5m, 1 kg E. 4 N/M, stretched 0.5m, 4 kg F. 1 N/M, stretched 0.5m, 5 kg

Explanation / Answer

= k/m = 2/T Thus 2/T = k/m and T = 2 * m/k A : 2.80 s B: 3.97 s C: 7.02 s D: 3.14 s E: 3.14 s F: 14.04 s F > C > B > D,E > A

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