A particle passes through the origin with a velocity of6.3m/s, vector y. If the

Question

A particle passes through the origin with a velocity of6.3m/s, vector y. If the particle's acceleration is (-4.4m/s^2 )vector x.(a)What are its x and ypositions after 5.0s? (b) What are Vx and Vy at this time? Does the speed of thisparticle increase with time, decrease with time, or increase and then decrease?Expain. A particle passes through the origin with a velocity of6.3m/s, vector y. If the particle's acceleration is (-4.4m/s^2 )vector x.(a)What are its x and ypositions after 5.0s? (b) What are Vx and Vy at this time? Does the speed of thisparticle increase with time, decrease with time, or increase and then decrease?Expain.

Explanation / Answer

    (a) X = Xo + Vxo*t + 0.5*Ax*t*t              =0 + 0 + 0.5*(-4.4)*5*5 = -55 m           Y = Yo+ Vyo*t + 0.5*Ay*t*t             = 0 + 6.3*5 + 0 = 31.5 m     (b) Vx = Vxo + Ax*t = 0 + (-4.4)*5 =-22 m/s           Vy= Vyo + Ay * t    = 6.3 m/s           Sincethe speed of the particle is dependent only on the individualmagnitudes of Vx and Vy,            V = [Vx2 + Vy2]        Vy is constant and |Vx|increases from zero at Ax*t m/s its speed onlyincreases.         

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