A 1000 kg sports car with a a 71 kg drivercrosses the rounded top of a hill (rad

Question

A 1000 kg sports car with a a 71 kg drivercrosses the rounded top of a hill (radius = 100 m) at 22 m/s. (Include the mass of the driver, whereappropriate.) (a) Determine the normal force exerted by theroad on the car.
1 N

(b) Determine the normal force exerted by the car on the71 kg driver.
2 N

(c) Determine the car speed at which the normal force on the driverequals zero.
3 m/s (a) Determine the normal force exerted by theroad on the car.
1 N

(b) Determine the normal force exerted by the car on the71 kg driver.
2 N

(c) Determine the car speed at which the normal force on the driverequals zero.
3 m/s

Explanation / Answer

             Given that the mass of the car is m = 1000 kg              mass of the diver is M = 71 kg              The radius of the hill is r = 100 m               The velocity of the car is v = 22 m/s      --------------------------------------------------------------------------             --------------------------------------------------------------      (a)   The normal forceexerted by the road on the car.
                      (m+M)v2 / r + N = (M+m)g                                      N= (M+m)g -  (M+m)v2 / r                                          =  ------------- N           (b)   Thenormal force exerted by the car on the person.
                      (m)v2 / r + N = (m)g                                       N =(m)g -  (m)v2 / r                                          =  ------------- N        (c) substitude the N= 0in above equation we get                                                          mv2/ r = mg                                         v = gr                                           =--------- m/s             --------------------------------------------------------------      (a)   The normal forceexerted by the road on the car.
                      (m+M)v2 / r + N = (M+m)g                                      N= (M+m)g -  (M+m)v2 / r                                          =  ------------- N           (b)   Thenormal force exerted by the car on the person.
                      (m)v2 / r + N = (m)g                                       N =(m)g -  (m)v2 / r                                          =  ------------- N        (c) substitude the N= 0in above equation we get                                                   (m)v2 / r + N = (m)g                                       N =(m)g -  (m)v2 / r                                          =  ------------- N        (c) substitude the N= 0in above equation we get                              mv2/ r = mg                                         v = gr                                           =--------- m/s       

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