What are the magnitude and direction of the electric field at apoint midway betw

Question

What are the magnitude and direction of the electric field at apoint midway between a -7.0 µCand a +6.0 µC charge 4.0 cm apart? Assume no other charges arenearby.
Magnitude
1 N/C
Direction 2 perpendicular to the line between thecharges
none ofthese
towardthe positive charge
towardthe negative charge
2 perpendicular to the line between thecharges
none ofthese
towardthe positive charge
towardthe negative charge
2 perpendicular to the line between thecharges
none ofthese
towardthe positive charge
towardthe negative charge

Explanation / Answer

E field from the -7.0 charge is .      E = k q /r2 = 8.99 x 109 * 7.0 x10-6 / 0.022 = .          = 1.57325 x 108 . E field from the 6.0 charge is .      E = k q /r2 = 8.99 x 109 * 6.0 x10-6 / 0.022 = .          = 1.34850 x 108 . total E field is    1.34850 + 1.57325 =    2.92 x 108   N/C     TOWARD THE NEGATIVE CHARGE . E field from the 6.0 charge is .      E = k q /r2 = 8.99 x 109 * 6.0 x10-6 / 0.022 = .          = 1.34850 x 108 . total E field is    1.34850 + 1.57325 =    2.92 x 108   N/C     TOWARD THE NEGATIVE CHARGE . total E field is    1.34850 + 1.57325 =    2.92 x 108   N/C     TOWARD THE NEGATIVE CHARGE

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.