A rotating door is made from four rectangular sections. Themass of each section

Question

A rotating door is made from four rectangular sections. Themass of each section is 72 kg. Aperson pushes on the outer edge of one section with a force ofF = 78 N that is directedperpendicular to the section. Determine the magnitude of the door'sangular acceleration.
r= 1.2m
How can I find the angular acceleration? A rotating door is made from four rectangular sections. Themass of each section is 72 kg. Aperson pushes on the outer edge of one section with a force ofF = 78 N that is directedperpendicular to the section. Determine the magnitude of the door'sangular acceleration.
r= 1.2m
How can I find the angular acceleration?

Explanation / Answer

If r = width of a section then I = 1/3 M r2    since this themoment of inertia of a rod (about one end) of mass M andlength r because the door can be considered as composed of any numberof rods of length r F r = I        torque = moment of inertia * angular acceleration = 3 F / (M r)    where M = 4 * 72 kg =288 kg = 234 / (288 * 1.2) = .68 rad /s2

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