A room is 6.5 m by 6 m by 3 m. (a) If the air pressure in the room is 1 atm and

Question

A room is 6.5 m by 6 m by 3 m.

(a) If the air pressure in the room is 1 atm and the temperature is 293 K, find the number of moles of air in the room.

______________ mol


(b) If the temperature rises by 5 K and the pressure remains constant, how many moles of air leave the room?

______________ mol



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a) I have n = 63 * 10^3 = 63000/24.0553 = 2618.965 moles but I dont know if 2618.965 is correct.

I got 24.0553 from 300 K / 24.63 = 293 K / X where X is equal to 24.0553

Explanation / Answer

volume V = 6.5 m * 6 m * 3 m = 117 m^ 3 pressure P = atm = 1.013 * 10 ^ 5 Pa temeprature T = 293 K from the relation PV = nRT No.of moles n = PV / RT where R = gas constant = 8.314 J / mol K plug the values we get n = 4865.4 mol (b). At constant pressure and volume , n ' / n = T ' / T where T ' = final temp = 293 + 5 = 298 K from this final No.of moles n ' = ( T ' / T ) n = 4948.42 moles No.of moles of air leave the room = n ' - n = 83 moles

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