A solid cylinder, with a height of 4.00 m, is floating atthe interface between w

Question

A solid cylinder, with a height of 4.00 m, is floating atthe interface between water and oil in an open container that is16.00 m in height. There is a height of 8.0 m for oil and aheight of 8.0 m for water. The height of the cylinder that isjust in the oil layer is 1.25 m and 2.75 m in water. Thedensity of oil is 725 kg/m^3 and the density of water is 1000kg/m^3.
What is the density of the solid cylinder?
What is the absolute pressure at the top surface of the cylinderand the bottom of the cylinder (Patm = 1.01 x 10^5 Pa).
density (p) = mass/volume weight=(pV)g A solid cylinder, with a height of 4.00 m, is floating atthe interface between water and oil in an open container that is16.00 m in height. There is a height of 8.0 m for oil and aheight of 8.0 m for water. The height of the cylinder that isjust in the oil layer is 1.25 m and 2.75 m in water. Thedensity of oil is 725 kg/m^3 and the density of water is 1000kg/m^3.
What is the density of the solid cylinder?
What is the absolute pressure at the top surface of the cylinderand the bottom of the cylinder (Patm = 1.01 x 10^5 Pa).
density (p) = mass/volume weight=(pV)g

Explanation / Answer

W = w Vw g + oVog        weight of cylinder= weight of liquids displaced W = c A Lg        where L is the lengthof the cylinder and A the area of a cross section of thecylinder Vw = 2.75 A   and Vo = 1.25 A Then c L = 2.75w + 1.25 o c = 914 kg / m3 PT = PA + og * 6.75    pressure at top = atmosphericpressure + pressure due to 6.75 m oil PB = PA + og * 8 + w g *2.75      absolute pressure at bottom ofcylinder PT = PA + og * 6.75    pressure at top = atmosphericpressure + pressure due to 6.75 m oil PB = PA + og * 8 + w g *2.75      absolute pressure at bottom ofcylinder

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