A spring lies on a horizontal table, and the left end of thespring is attached t

Question

A spring lies on a horizontal table, and the left end of thespring is attached to a wall. The other end is connected to a box.The box is pulled to the right, stretching the spring. Staticfriction exists between the box and the table, so when the springis stretched only by a small amount and the box is released, thebox does not move. The mass of the box is 0.55 kg, and the springhas a spring constant of 54 N/m. The coefficient of static frictionbetween the box and the table on which it rests iss = 0.68. How far can the spring bestretched from its unstrained position without the box moving whenit is released?

Explanation / Answer

      Given that the mass of box is m =0.55 kg       Force constant is K = 54 N/m       The coefficient of staticfriction is s = 0.68 ------------------------------------------------------ If the box not moving   spring force balanced bythe frictional force                        s*mg = kx                               x = s*mg / k                                    = 0.067 m                                    = 6.7 cm                                    = 67 mm

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