A person is riding a bicycle, and its wheels have an angularvelocity of +20.5rad

Question

A person is riding a bicycle, and its wheels have an angularvelocity of +20.5rad/s. Then, the brakes are applied and the bike is brought to auniform stop. During braking, the angular displacement of eachwheel is +12.0revolutions. (a) How much time does it take for the bike tocome to rest?
Enter anumber. 1 s

(b) What is the angular acceleration of each wheel?
Enter anumber. 2 rad/s2 (a) How much time does it take for the bike tocome to rest?
Enter anumber. 1 s

(b) What is the angular acceleration of each wheel?
Enter anumber. 2 rad/s2 Enter anumber. Enter anumber.

Explanation / Answer

From rotational dynamics 2 = f2-i2 then = (f2-i2 ) / 2 = -(20.5rad/s)2 / 2(12*2) rad = 2.788rad/s2 (a) f =i  +t        t =i / = 20.5 rad/s / 2.788 =  7.35s (b) Angular acceleration = 2.788rad/s2

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