A person is riding a bicycle, and its wheels have an angularvelocity of +18.5rad

Question

A person is riding a bicycle, and its wheels have an angularvelocity of +18.5rad/s. Then, the brakes are applied and the bike is brought to auniform stop. During braking, the angular displacement of eachwheel is +11.5revolutions. (a) How much time does it take for the bike tocome to rest?
    ??? s

(b) What is the angular acceleration of each wheel?
   ??? rad/s2 (a) How much time does it take for the bike tocome to rest?
    ??? s

(b) What is the angular acceleration of each wheel?
   ??? rad/s2

Explanation / Answer

               Given that the initial angular velocity is 1 = 18.5rad/s                 Theangular displacement is = 11.5 rev = (11.5rev)(2rad/rev) = 72.22 rad                The final angular velocity is 2 = 0 rad/s     ------------------------------------------------------------------------------------------                From the equation of motion the final angular velocity is22 = 12 +2               where is the angular velocity of the body                             then    = ( 22 -12 ) / 2                                           = -------------- rad/s2            then the time taken to stop is t = ( 2 -1 ) /                                                          = ---------- sec                    then the time taken to stop is t = ( 2 -1 ) /                                                          = ---------- sec                   

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