A person in a boat sees a fish in the water of index 1.33 at an angle of 35? rel

Question

A person in a boat sees a fish in the water of
index 1.33 at an angle of 35? relative to the
water’s surface.
What is the true angle relative to the water’s surface?
Answer in units of ?.

side note:
angle in incidence from the normal which would be from y axis, i believe what is given(35) must be subtracted from 90:
90-35=which will give me the angle of incidence in medium one which would be air, to find the true angle relative to the water's surface we would have to use n1sintheta1=n2sintheta2 1sintheta(90-35)=1.33sintheta2) i got 38.017 please help me with my logic, perhaps I am over thinking what "angle relative to water's surface" means. THANKS!
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90-35=which will give me the angle of incidence in medium one which would be air, to find the true angle relative to the water's surface we would have to use n1sintheta1=n2sintheta2 1sintheta(90-35)=1.33sintheta2) i got 38.017 please help me with my logic, perhaps I am over thinking what "angle relative to water's surface" means. THANKS!
____________________________________________-

Explanation / Answer

index of refraction of water n = 1.33 angle of relative to the water’s surface theta = 35 degrees angle relative to normal theta 1 = 90 - theta = 55 degrees required true angle relative to the water’s surface theta ' =? we know n1sintheta1=n2sintheta2 1*sintheta(90-35)=1.33*sintheta2 theta 2 =38.017 degrees relative to normal angle relative to water surface = 90 - theta2 = 51.98 degrees

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