A person eats a container of strawberry yogurt. The Nutritional Facts label stat

Question

A person eats a container of strawberry yogurt. The Nutritional Facts label states that it contains 267 Calories (1 Calorie = 4186 J). What mass of perspiration would one have to lose to get rid of this energy? At body temperature, the latent heat of vaporization of water is 2.42 x 106 J/kg. the tolerance is +/-2% A person eats a container of strawberry yogurt. The Nutritional Facts label states that it contains 267 Calories (1 Calorie = 4186 J). What mass of perspiration would one have to lose to get rid of this energy? At body temperature, the latent heat of vaporization of water is 2.42 x 106 J/kg. the tolerance is +/-2%

Explanation / Answer

enenrgy due to eating of strawberry yogurt E = 267 Cal = 267 * 4186 J the latent heat of vaporization of water is L = 2.42 x 10^6 J/kg mass of perspiration would one have to lose to get rid of this energy is M = E / L plug the values we get M = 0.4618 kg

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