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A block of mass 2.50 kg is pushed 2.60 m along a frictionless horizontal table b

ID: 1724362 • Letter: A

Question

A block of mass 2.50 kg is pushed 2.60 m along a frictionless horizontal table by aconstant 16.0 N force directed 25.0°below the horizontal. (a) Determine the work done by the appliedforce.
1 J
(b) Determine the work done by the normal force exerted by thetable.
2 J
(c) Determine the work done by the force of gravity.
3 J
(d) Determine the work done by the net force on the block.
4 J
A block of mass 2.50 kg is pushed 2.60 m along a frictionless horizontal table by aconstant 16.0 N force directed 25.0°below the horizontal. (a) Determine the work done by the appliedforce.
1 J
(b) Determine the work done by the normal force exerted by thetable.
2 J
(c) Determine the work done by the force of gravity.
3 J
(d) Determine the work done by the net force on the block.
4 J
(a) Determine the work done by the appliedforce.
1 J
(b) Determine the work done by the normal force exerted by thetable.
2 J
(c) Determine the work done by the force of gravity.
3 J
(d) Determine the work done by the net force on the block.
4 J

Explanation / Answer


   we are given with
   mass of the block M = 2.50 kg
   displacement of the block s = 2.60 m
   force F = 16.0 N
   angle = 25o
   acceleration due to gravity g = 9.80 m /s2  
   if M g is the weight of the block and R is thereaction force then
(a)
   the work done by the applied force will be
   W = F cos s
       = ...... J
(b)
   the work done by normal force exerted by thetable will be   
   W = R s cos90o
   but we can see that the force and the displacement areperpendicular to each other the work
   done will be zero
   W = 0 J
(c)
   work done by the force of gravity is
   W = M g s cos90o
   but we can see that displacement and the weightof the block are perpendicular to each other the
   workdone will be zero
   so we get
   W = 0 J
(d)
   the work done by the net force on the block is W inpart (a)

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