A particles position is given by x = (5+40t-8t 3 )m,where t is the time in secon

Question

A particles position is given by x = (5+40t-8t3)m,where t is the time in seconds. Find ax at t=2s. A)-152m/s2 B)-96m/s2 C)-56m/s2 D)21m/s2 E)96m/s2 Hint: This is a calculus problem. x=(5+40t-8t3) vx=dx/dt=40-24t2 ax=dvx/dt=-48t Now plug in the time: ax(2s)=-48*2 m/s2 Remember: always differentiate first then plug in thenumbers A particles position is given by x = (5+40t-8t3)m,where t is the time in seconds. Find ax at t=2s. A)-152m/s2 B)-96m/s2 C)-56m/s2 D)21m/s2 E)96m/s2 Hint: This is a calculus problem. x=(5+40t-8t3) vx=dx/dt=40-24t2 ax=dvx/dt=-48t Now plug in the time: ax(2s)=-48*2 m/s2 Remember: always differentiate first then plug in thenumbers Remember: always differentiate first then plug in thenumbers

Explanation / Answer

given equation         .x=(5+40t-8t3) then vx=dx/dt= 0 + 40-24t2 and ax=dvx/dt= 0 + (-48t) Now plug in the time:      ax(2s)= -48*2m/s2 = -96 m/s2

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