A particle with charge q = + 7.2 x 10^-9C is moving in a region containing both

Question

A particle with charge q = +7.2x 10^-9C is moving in a region containing both an electric field and a magnetic field. The strength of the electric field is 2.5 x 10^5 N/C, and the strength of the magnetic field is 0.24 T.

a) What is the magniyude of the electric force acting on the particle?

b) How fast must the particle be moving so that the net force acting on the particle is zero?

Assume that the particle is moving perpendicular to the magnetic field and that the gravitational force acting on the particle is negligible.

c) If the electric field points to the right and the particle is moving up, what is the direction of the magnetic field?

d) If the particle were negatively charged (instead of positively charged),the directions of which of the following would change? ( Select all that apply.)

( ) The electric field

( ) the magnetic field

( ) the electric force

( ) the magnetic force.

Explanation / Answer

a) F = q E = 7.2E-9*2.5E5=0.0018 N

b) to cancel
qv B = q E
v = E/b = 2.5E5/0.24=1.042E6 m/s

c) into the page

d) both forces would flip

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.