A particles position along the x-axis is described by the function x(t)= A(t) +B

Question

A particles position along the x-axis is described by the function x(t)= A(t) +Bt^2
A=-2.1m/s B=2.1m/s^2
Enter an expression in terms of A, B and t for the velocity of the particle as a function of time At what time is the particles velocity zero? A particles position along the x-axis is described by the function x(t)= A(t) +Bt^2
A=-2.1m/s B=2.1m/s^2
Enter an expression in terms of A, B and t for the velocity of the particle as a function of time At what time is the particles velocity zero?
A=-2.1m/s B=2.1m/s^2
Enter an expression in terms of A, B and t for the velocity of the particle as a function of time At what time is the particles velocity zero?

Explanation / Answer

here,

x = A * ( t) + B * t^2

differentiating the equation for velocity

v = A + 2 * B * t

the expression for v as a function of time is v = A + 2 * B * t

for velocity = 0 m/s

0 = A + 2 * B * t

t = - A /2B

t = 2.1 /(2 * 2.1) s

t = 0.5 s

the velocity is zero at time t = 0.5 s

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