Figure 1 shows a closed tank which is completely filled with water and connected

Question

Figure 1 shows a closed tank which is completely filled with water and connected to a Mercury manometer which can be used to determine the water pressure inside the tank. A step shaped gate ABCD hinged (pin support) at A prevents the water from escaping. The gate has dimensions as shown and is 2 m wide into the page. The gate is held closed by a strut CF which is 4m long and made from steel rectangular hollow section (RHS): E = 200,000 MPa Oy 350 MPa. The strut is pinned at each end (C and F) for buckling about x and y axes and is laterally restrained at its mid-length (E) in the x direction only (affects buckling about the y axis). If the height of mercury in the manometer is 2m, using the attached table (Figure 2) determine the lightest (kg/m) RHS section size for the strut CF that will prevent the strut from failing and releasing the water. Which mode of failure (squashing, buckling about X or buckling about Y) governs the axial compressive capacity of the strut CF? Mercury pg = 133420 N/m2 Water: g-9810 N/m3 2.5 m 45° 2my Lateral restraint in x direction 2 m affects buckling about y-axis) Gate ABCD is 2m wide into the page Figure 1

Explanation / Answer

After Calculations,

1. The lightest Wieht material for Rectangular Hollow Section is 150X50X5mm size

2. Since it is laterally restrained in X- direction, Buckling in Y direction may be the governing condition.

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