Figure 1 -55 shows the trajectory of a ball traveling through the air. affected

Question

Figure 1 -55 shows the trajectory of a ball traveling through the air. affected hv both gravity and air resistance. Here are the positions of the ball at several successive times: What is the average velocity of the ball as it travels between location A and location B? If the ball continued to travel at the same average velocity during the next second, where would it be at the end of that second? (That is. where would it be at time t = 2 seconds?) How does your prediction from part (b) compare to the actual position of the ball at t = 2 seconds (location C)? If the predicted and observed locations of the ball are different, explain why.

Explanation / Answer

Average velocity = total displacement / total time displacement betweeen points A and B = < 22.3 -0 , 26.1-0 , 0 > = < 22.3 , 26.1 , 0 > => Average velocity = ( 22.3 i + 26.1j + 0 ) / 1 = ( 22.3 i + 26.1j + 0 ) m/s < 22.3 , 26.1 , 0 > m/s

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