Figure 1 (figure to the left) is not spinning. Figure 2 (figure to the right) is
ID: 2055683 • Letter: F
Question
Figure 1 (figure to the left) is not spinning. Figure 2 (figure to the right) is spinning.
Figure 1 shows the apparatus when it is not spinning. When it is spinning and the spinning speed is just right, the apparatus looks like in Figure 2, where the string is vertical. You use a stop watch to measure the total time for 20 revolutions, and the stop watch reads 13.68 seconds.
(a) (1 point) Find the period of the circular motion.
(b) (1 point) If the radius of the circular motion is 16 cm, find the speed of the circular motion.
(c) (1 point) Calculate the magnitude of the centripetal acceleration.
(d) (1 point) If the mass M = 200 g, calculate the magnitude of the centripetal force.
(e) (1 point) In Figure 2, which force is the centripetal force?
Explanation / Answer
1)
T = 13.68s/20revolutions = 0.684 s
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2)
= 2/T = 2*3.14/0.684 = 9.181
v = R = 0.16 * 9.181 = 1.46896 m/s
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3)
a = v2/R = (1.46896)2/R = 13.487 m/s^2
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4)
F = ma = (0.200) * 13.487 = 2.6974 N
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5)
Both of the Fweight and Felastic (a super position of them)
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