Figure ( a ) shows a lens with radius of curvature R = 266 mm lying on a flat gl

Question

Figure (a) shows a lens with radius of curvature R = 266 mm lying on a flat glass plate and illuminated from above by light with wavelength gamma . Figure (b) (a photograph taken from above the lens) shows that circular interference fringes (called Newton's rings) appear, associated with the variable thickness d of the air film between the lens and the plate. Find the radius r of the interference maxima (m = 1, gamma  = 551 nm) assuming r/R << 1.

Please show work, final answer in mm

shows a lens with radius of curvature R = 266 mm lying on a flat glass plate and illuminated from above by light with wavelength gamma . Figure (b) (a photograph taken from above the lens) shows that circular interference fringes (called Newton's rings) appear, associated with the variable thickness d of the air film between the lens and the plate. Find the radius r of the interference maxima (m = 1, gamma = 551 nm) assuming r/R

Explanation / Answer

from figure r/R = sin?
so r= R*sin45 = (266*10^-3) = 188*10^-3 = 188mm
  
so r= R*sin45 = (266*10^-3) = 188*10^-3 = 188mm
  

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