A projectile is fired with an initial velocity in the x direction of 2.7 m/sec a

Question

A projectile is fired with an initial velocity in the x direction of 2.7 m/sec and an initial velocity in the y direction of 6.6 m/sec. At what angle with respect to the x axis was the projectile fired? I got that the angle is 67.75 and the resultant initial velocity is 7.13 m/s but I do not know how to find the following: How far in the +y direction will the projectile travel before its velocity in the y direction is 0? (acceleration due to gravity is 10 m/s^2). Please help asap I will give you the highest amount of points I can possibly give!

Explanation / Answer

the gravity acceleration is g. so time needed for the vertical component of velocity to become zero t=vy/g=6.6/10=0.66(s). so that we have y=vy*t-gt^2/2 where t=0.66(s) so y=2.22(m)

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