A 1500-kg automobile travels at a speed of 25 m/s along a straight concrete high

Question

A 1500-kg automobile travels at a speed of 25 m/s along a straight concrete highway. Faced with an emergency situation, the driver jams on the brakes, and the car skids to a stop. What will be the car’s stopping distance be for (a) dry pavement and (b) wet pavement?
A 1500-kg automobile travels at a speed of 25 m/s along a straight concrete highway. Faced with an emergency situation, the driver jams on the brakes, and the car skids to a stop. What will be the car’s stopping distance be for (a) dry pavement and (b) wet pavement?

Explanation / Answer

as per the situation
kinetic energy=breaking force*stopping distance
from the data we can calculate kinetic energy (1/2mv*v) since mass and velocity of the automobile are given. but neither magnitude of break force or decelerating capacity of the breakes is given.
so if you find those values in the original problem please use them and solve the problem by using the formula
kinetic energy=breaking force*stopping distance on wet surface we need anopther quantity that is coefficient of friction .

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