A hockey puck struck by a hockey stick is given an initial speed v 0 in the posi

Question

A hockey puck struck by a hockey stick is given an initial speed v0 in the positive x-direction. The coefficient of kinetic friction between the ice and the puck is µk.
(a) Obtain an expression for the acceleration of the puck. (Use the following as necessary: µk and g.)
(b) Use the result of part (a) to obtain an expression for the distance d the puck slides. The answer should be in terms of the variables v0, µk, and g only.


A hockey puck struck by a hockey stick is given an initial speed v0 in the positive x-direction. The coefficient of kinetic friction between the ice and the puck is µk.
(a) Obtain an expression for the acceleration of the puck. (Use the following as necessary: µk and g.)
(b) Use the result of part (a) to obtain an expression for the distance d the puck slides. The answer should be in terms of the variables v0, µk, and g only.

Explanation / Answer

a) Step 1:As initially the puck is travelling along +ve x-axis,so force acting on the puck will be the frictional force f whose direction is along -ve x-axis.
Step 2:Now by Newton's II law of motion ,f=ma(m is the mass of the puck)
But f=µkN(N is the normal reaction and is equal to weight mg of the puck in this case)
Therfore,-ma=µkN(direction of frictional force is opposite to direction of motion) or -ma=µkmg so,a=-µkg b)Now by applying the equation v^2=vo^2 +2ad for motion in one dimension,we can find the distance the puck slides before coming to rest. Since final velocity of the puck is 0, vo^2 +2ad=0 or vo^2=-2ad Putting the value of a from the first part of the question, vo^2=-2(-µkg)d Hence,d=vo^2/2µkg

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