i have no idea how to even go about this! someone please help me!! A 18.0 kg blo

Question

i have no idea how to even go about this! someone please help me!!

A 18.0 kg block is initially at rest on a horizontal surface. A horizontal force of 86.0 N is required to set the block in motion. After it is in motion, a horizontal force of 54.0 N is required to keep the block moving with constant speed. Find the coefficients of static and kinetic friction from this information.

Explanation / Answer

weight of body = 18*10 = 180N so, normal reaction on the body ,N= 180N Static Friction force,Fs = Cs*N (Cs is coefficient of static friction) 86 = Cs*180 =>Cs = 86/180 = 43/90 = 0.477778 Kinetic friction force,Fk = Ck*N(Ck is coefficient of kinetic friction) 54 = Ck*180 Ck = 54/180 = 0.3

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.