A solid aluminum sphere has a radius of .50m and a temp of75C. The sphere is com

Question

A solid aluminum sphere has a radius of .50m and a temp of75C. The sphere is completely immersed in a pool of water whose temis 25C. The sphere cools, while the water temp remains nearly 25C,bc it is a large pool. The sphere is weighed in the waterimmediately after being submerged and then again after cooling to25C. a) Whicj weight is larger? b) Use Archimedes' principle to find the magnitude of thedifference bt the weights. A solid aluminum sphere has a radius of .50m and a temp of75C. The sphere is completely immersed in a pool of water whose temis 25C. The sphere cools, while the water temp remains nearly 25C,bc it is a large pool. The sphere is weighed in the waterimmediately after being submerged and then again after cooling to25C. a) Whicj weight is larger? b) Use Archimedes' principle to find the magnitude of thedifference bt the weights.

Explanation / Answer

Since the sphere shrinks in volume when it cools it becomesmore dense ( =M / V) It will weight less at the cooler temperature (in water) sinceless water is displaced providing less buoyancy. R75 = R25 (1 + T) =R25 (1 + 50 ) V25 = 4/3 R325      V75 = 4/3 [R25 (1 + T)]3 V = 4/3 R253 [ (1 + T)3 - 1) W = g V     theapparent change in weight due to weight of water of volume anddensity of 1000 kg / m3 Use the coefficient of linear expansion for Al and findR25 and make the necessary substitutions R25 = R75 /(1 + T) Use the coefficient of linear expansion for Al and findR25 and make the necessary substitutions R25 = R75 /(1 + T)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.