A particle of mass m=5.00x10^-5kg and a charge q=2.00x10^-5Chas an initial speed

Question

A particle of mass m=5.00x10^-5kg and a charge q=2.00x10^-5Chas an initial speed of 5.00m/s at point A. The particle is locatedin a uniform electric field. As the particle moves to position Balong the electric field direction. The potential differencebetween A and B is 10volts, what is the speed of this particle atpoint B? A particle of mass m=5.00x10^-5kg and a charge q=2.00x10^-5Chas an initial speed of 5.00m/s at point A. The particle is locatedin a uniform electric field. As the particle moves to position Balong the electric field direction. The potential differencebetween A and B is 10volts, what is the speed of this particle atpoint B?

Explanation / Answer

   Change in k.e. of particle in potentialdifference    K   =   q *V    (1/2) * m *(vA2   -   vB2)   =   q* V    (1/2) * 5.00 * 10-5 *(5.002   -   vB2)   =   2.00* 10-5 * 10    25.00 - vB2   =   2* 20 / 5.00    vB2   =   25.00- 8.00    Speed atB      vB   =   (17.00)                                  =   4.123   m/s

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