A wheel of radius 0.700 m, which is movinginitially at 35.0 m/s, rolls to a stop

Question

A wheel of radius 0.700 m, which is movinginitially at 35.0 m/s, rolls to a stop in160 m. (a) Calculate the magnitude of its linearacceleration.
1______________ m/s2

(b) Calculate the magnitude of its angular acceleration.
2rad/s2

(c) The wheel's rotational inertia is 0.170 kg·m2 about its central axis.Calculate the magnitude of the torque about the central axis due tofriction on the wheel.
3 N·m (a) Calculate the magnitude of its linearacceleration.
1______________ m/s2

(b) Calculate the magnitude of its angular acceleration.
2rad/s2

(c) The wheel's rotational inertia is 0.170 kg·m2 about its central axis.Calculate the magnitude of the torque about the central axis due tofriction on the wheel.
3 N·m

Explanation / Answer

a) we know that          v2 -u2 = 2as ==> a = - u*u / 2s             = - 35 * 35 / 2*160             = - 3.828 m/s2 b) = a / r = - 3.828 / 0.700 = - 5.468 rad /s2 (c) = I = 0.170 * 5.468 = 0.9296 N-m

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