The question states: At what projection angle will the range of aprojectile be e

Question

The question states: At what projection angle will the range of aprojectile be equal to its maximum height?
Should you just equate the two equations for range and heightand solve for theta?
i.e. Voy2 / 2g = Vo2 sin 2?
Once I solve for theta, if this is correct, howwould I go about finding the answer quantitatively? There must besome simple connection I'm missing.
Thanks for your help.
Should you just equate the two equations for range and heightand solve for theta?
i.e. Voy2 / 2g = Vo2 sin 2?
Once I solve for theta, if this is correct, howwould I go about finding the answer quantitatively? There must besome simple connection I'm missing.
Thanks for your help.

Explanation / Answer

The projection angle is 75.96o When           (V sin )2/ 2g = Vo2 sin 2 / g From this we get             tan = 4       ==> = 75.96o

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.