The question is: In a population of 200 individuals, 72 are homozygousrecessive

Question

The question is:
In a population of 200 individuals, 72 are homozygousrecessive (cc) for the character of eye color. What is thefrequency of the dominant allele? Answer choices: a.) 0.16 b.) 0.36 c.) 0.40 d.) 0.48 e.) 0.60
I reasoned that the freq. of the recessive allele is .36, sothe dominant allele must be 0.64, so I couldn't get a correctanswer. Is this the wrong way to go about it?? Any help would begreatly appreciated! Thank you!
In a population of 200 individuals, 72 are homozygousrecessive (cc) for the character of eye color. What is thefrequency of the dominant allele? Answer choices: a.) 0.16 b.) 0.36 c.) 0.40 d.) 0.48 e.) 0.60
I reasoned that the freq. of the recessive allele is .36, sothe dominant allele must be 0.64, so I couldn't get a correctanswer. Is this the wrong way to go about it?? Any help would begreatly appreciated! Thank you!

Explanation / Answer

         q=frequency of recessive allele          p2 =percentage of homozygousdominant          q2=percentage of homozygousrecessive
so, 72 are homozygous recessive out of 200 individuals, andthe percentage is 0.36(q2), so the frequency ofrecessive allele is square root of 0.36, which is 0.6 (q). So, if qis equal to 0.6, then p is equal to 1-0.6=0.4. Thep(frequency of dominant allele is 0.4.

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