A wire runs through a pool of water with a current of 3A.There is also a reisita

Question

A wire runs through a pool of water with a current of 3A.There is also a reisitance of 50 ohms. So to heat of water , a 3A current is sent thorugh a resistorof resistance 50 ohms. A. What is the power dissipation? (energy per unit time) B. If this runs for 2 minutes, what is the total thermalenergy generated? C. For 2 kg of water initially at 20 degrees Celsius, what isthe final temperature? (after 2 minutes of heating? I don't know how the solve but here are the answers A. 450W    B. 54,000J    C. 26.45 Celsius A wire runs through a pool of water with a current of 3A.There is also a reisitance of 50 ohms. So to heat of water , a 3A current is sent thorugh a resistorof resistance 50 ohms. A. What is the power dissipation? (energy per unit time) B. If this runs for 2 minutes, what is the total thermalenergy generated? C. For 2 kg of water initially at 20 degrees Celsius, what isthe final temperature? (after 2 minutes of heating? I don't know how the solve but here are the answers A. 450W    B. 54,000J    C. 26.45 Celsius

Explanation / Answer

given that I = 3A R = 50 power = I2R            =( 3A)2 *50 =450W power = w/t thermal energy generated = w = power * t                                              = 450W * 2 * 60 s = 54000J

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