Light of wavelength 800 nm is incident on the face of a silica prism (the prism

Question

Light of wavelength 800 nm is incident on the face of a silica prism (the prism is long and extended perpendicular to the plane of the figure) at an angle incidence of theta1 = 69degree. The apex angle of the prism is Phi = 55.7degree. Given: The value of the index of refraction for silica is n = 1.455. Find the angle of refraction at this first surface. Answer in units of degree. Find the angle of incidence at the second surface. Answer in units of degree. Find the angle of refraction at the second surface. Answer in units of degree.

Explanation / Answer

The angle of incidence 1 = 69o The apex angle of the prism = 55.7o Refractive index of silica prism n = 1.455 Angle of refraction at the first surface is 2 =? We know that                        n = sin1 / sin2     1.455 = sin69 / sin2    sin2 = sin69 / 1.455    2 = 39.91o The angle of incidence at the second surface 3 = ? We know that apex angle = 2 +3                                     55.7o = 33.91o + 3                                      3 = 21.79o The angle of refraction at the second surface 4 =? We know that                = sin4 / sin3             sin4 = sin3                      = 1.455 sin21.79                 4 = 32.69o

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