Light of frequency f = 6.0 times 10^14 hz strikes a glass- air boundary at an an

Question

Light of frequency f = 6.0 times 10^14 hz strikes a glass- air boundary at an angle of incidence theta1. The ray is partially reflected and partially refracted at the boundary as shown. The index of refraction of this glass is 1.60 for light of this frequency. Determine the value of theta3 if theta1 = 30 degree Determine the value of theta2 if theta1 = 30 degree. Determine the speed of the light in this glass. Determine the wavelength of this light in the glass. what is the largest value of theta1 that will result in a refracted ray?

Explanation / Answer

here,

frequency of light , f = 6 * 10^14 Hz

index of refraction , n = 1.6

a)

theta1 = 30 degree

as the angle of reflection is equal to the angle of incidence

the angles , theta1 = theta3

theta3 = 30 degree

the angle of reflection is 30 degree

b)

using snell's law

sin(theta2) /sin(theta1) = n/1

theta2 = arcsin( sin(30) * 1.6)

theta2 = 53.13 degree

the angle theta2 is 53.13 degree

c)

the speed of light in glass , v = 3*10^8 /1.6

v = 1.875 *10^8 m/s

the speed of light in the glass is 1.88 * 10^8 m/s

d)

the wavelength of light , lamda = v/f

lamda = 1.875 * 10^8 /( 6 * 10^14)

lamda = 3.13 * 10^-7 m

the wavelength of light is 3.13 *10^-7 m

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