A firefighter with a weight of 715 Nslides down a vertical pole with an accelera

Question

A firefighter with a weight of 715 Nslides down a vertical pole with an acceleration of 2.85 m/s2, directed downward. (a) What are the magnitude and direction of thevertical force (use up as the positive direction) exerted by thepole on the firefighter?
N

(b) What are the magnitude and direction of the vertical force (useup as the positive direction) exerted by the firefighter on thepole?
N (a) What are the magnitude and direction of thevertical force (use up as the positive direction) exerted by thepole on the firefighter?
N

(b) What are the magnitude and direction of the vertical force (useup as the positive direction) exerted by the firefighter on thepole?
N

Explanation / Answer

(a) The force exerted by the pole on the firefighter isfrictional force          It actsupward.Therefore           mg - fk =ma         ==> fk = m ( g +a)                    = (715/9.8) ( 9.8 + 2.85)    = 922.93 N (b) fk = - 922.93 N

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