A 1000 kg boat moves through the water with two forces actingon it. One is a 300

Question

A 1000 kg boat moves through the water with two forces actingon it. One is a 3000 N forward push by the water on the propellor,and the other is an 2400 N resistive force due to the water aroundthe bow. a) What is the acceleration of the boat? b) if the boat starts from rest, how far will the boat move in10.0 s? c) what will its volocity be at the end of that time? A 1000 kg boat moves through the water with two forces actingon it. One is a 3000 N forward push by the water on the propellor,and the other is an 2400 N resistive force due to the water aroundthe bow. a) What is the acceleration of the boat? b) if the boat starts from rest, how far will the boat move in10.0 s? c) what will its volocity be at the end of that time?

Explanation / Answer

Given that          F = 3000N          Fr = 2400N         m =1000kg Therefore          F-Fr = ma ==> a = (F-Fr ) / m = 600/ 1000 = 0.60 m/s2 Using basic kinematic relation we have          S =0.5at2 = 0.5 * 0.60 * 100 = 30 m Velocity at the end of the time is         v = at = 0.6 * 10 = 6m/s

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