A 100-turn rectangular coil has of 0 400m times 0 300m, pivoted xl about the y-a

Question

A 100-turn rectangular coil has of 0 400m times 0 300m, pivoted xl about the y-axis, and its plane makes an angle 0-30 0degree with the x axis as shown The loop curries a current of 1 20A is the direction indicated and is in a uniform magnetic field directed in the direction magnitude of 0 BOOT. Calculate the magnetic moment of the loop and indicate the direction of the magnate moment on the diagram with respecting to x-axis Calculate the magnitude of the torque acting on the and the direction of the torque on diagram Determine the direction of the rotation of the loop.

Explanation / Answer

We know that,

a) magnetic dipole moment , m = NIA = 100* (1.2)*(0.4*0.3) = 14.4 A.m2 and +z direction

b)Torque = mxB = 14.4 * 0.8 sin30 = 5.76 N.m and +y axis direction

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