A 100-watt light bulp carries a current I. The total charge passing through it i

Question

A 100-watt light bulp carries a current I. The total charge passing through it in 60 minutes is 1800 C. How much is the current I? A) 0.5 A B) 1 A C) 30 A D) 60 A 7. Four 20-ohm resistors are connected in parallel and the combination is connected to a 20-V emf device. The current in any one of the resistors is: A) 1 A B) 4 A C) 5 A D) 8 A 8. Two identical capacitors, each with capacitance C, are connected in series and the combination is connected in parallel to a third identical capacitor. The equivalent capacitance of this arrangement is: A) 2C/3 B) C C) 3C/2 D) 2C E) 3C 9. A magnetic field exerts a force on a charged particle: A) always B) never C) if the particle is at rest D) if the particle is moving along the field lines E) if the particle is moving across the field lines

Explanation / Answer

6- A) 0.5A

I= DQ/DT so I =1800/60*60 =0.5 ampere

7-A) 1A

1/R = 1/20 +1/20; R=10 ohms

20=I*10, I=2 ampere both are parallel and equal resistance so 1 ampere passes through both

8- 3C/2

1/c(total of 2)=1/C +1/C ; c(total of 2) = C/2

It is in parallel with C so net capacitance=C/2 +C= 3C/2

9-E) if particle moves across the field

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