Figure 2-42 shows a simple device for measuring your reactiontime. It consists o
ID: 1667354 • Letter: F
Question
Figure 2-42 shows a simple device for measuring your reactiontime. It consists of a cardboard strip marked with a scale and twolarge dots. A friend holds the strip vertically, with thumb andforefinger at the dot on the right in Figure 2-42. You thenposition your thumb and forefinger at the other dot (on the left inFigure 2-42), being careful not to touch the strip. Your friendreleases the strip, and you try to pinch it as soon as possibleafter you see it begin to fall. The mark at the place where youpinch the strip gives your reaction time. (a) Howfar from the lower dot should you place the 50.0 ms mark? How muchhigher should you place the marks for (b) 100,(c) 150, (d) 200, and(e) 250 ms? (For example, should the 100 ms markerbe 2 times as far from the dot as the 50 ms marker? If so, give ananswer of 2 times. Can you find any pattern in the answers?)
Explanation / Answer
Given : The initial spped ( u ) = 0 The distance from the lower dot to the mark point As we know that S= u t + 1/2 at2 Where S is the distance a = g = 9.8 m/s2 S = 1/2 g t2 a ) at t = 50 ms = 50 *10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (50 * 10-3 )2 = ------ m b ) = ------ m b ) at t = 100 ms = 100 * 10-3s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (100 * 10-3)2 = ------ m c ) at t =150 ms = 150 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (150 * 10-3)2 = ------ m d ) at t =200 ms = 200 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (200 * 10-3)2 = ------ m e ) att = 250 ms = 250 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (250 * 10-3)2 = ------ m Solve it S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (100 * 10-3)2 = ------ m c ) at t =150 ms = 150 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (150 * 10-3)2 = ------ m d ) at t =200 ms = 200 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (200 * 10-3)2 = ------ m e ) att = 250 ms = 250 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (250 * 10-3)2 = ------ m Solve it = ------ m c ) at t =150 ms = 150 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (150 * 10-3)2 = ------ m d ) at t =200 ms = 200 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (200 * 10-3)2 = ------ m e ) att = 250 ms = 250 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (250 * 10-3)2 = ------ m Solve it S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (150 * 10-3)2 = ------ m d ) at t =200 ms = 200 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (200 * 10-3)2 = ------ m e ) att = 250 ms = 250 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (250 * 10-3)2 = ------ m Solve it = ------ m d ) at t =200 ms = 200 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (200 * 10-3)2 = ------ m e ) att = 250 ms = 250 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (250 * 10-3)2 = ------ m Solve it S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (200 * 10-3)2 = ------ m e ) att = 250 ms = 250 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (250 * 10-3)2 = ------ m Solve it = ------ m e ) att = 250 ms = 250 * 10-3 s S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (250 * 10-3)2 = ------ m Solve it S= 1/2 g t2 = 1/2 ( 9.8 m/s2 ) * (250 * 10-3)2 = ------ m Solve it = ------ m Solve itRelated Questions
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