A basketball of mass 0.60kg is dropped from rest from a height of1.22m. It rebou

Question

A basketball of mass 0.60kg is dropped from rest from a height of1.22m. It rebounds to a height of 0.69m. a) How muchmechanical energy was lost during the collision with the floor?
b) A basketball player dribbles the ball from a height of 1.22m byexerting a constant downward force on it for a distance of 0.13m.In dribbling, the player compensates for the mechanical energy lostduring each bounce. If the ball now returns to a height of1.22m, what is the magnitude of the force?
answer: a)3.1 J, b)24 N

Explanation / Answer

a)Let W is the mechanical energy W=mgh so W=mgh=3,1J. b) Since each time the ball colide with the ground it lose 3,1J So If the ball is able to reach the same height. It mean that the work that the force of the player acts on the ballis equal to 3,1 J A=F*d so F=A/d=3,1/0,13=24N

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