A baseball with a mass of 135 g is thrown horizontally with a speed of 41.0 m/s

Question

A baseball with a mass of 135 g is thrown horizontally with a speed of 41.0 m/s (92 mi/h) at a bat. The ball is in contact with the bat for 1.15 ms and then travels straight back at a speed of 45.9 m/s (103 mi/h). Determine the average force exerted on the ball by the bat. Neglect the weight of the ball (it is much smaller than the force of the bat) and choose the direction of the incoming ball to be positive. (Indicate the direction with the sign of your answer.) _____ N. A soccer ball player bounces the ball off her head, changing the velocity of the ball. She changes the x component of the velocity of the ball from v_ix = 7.9 m/s to v_fx = 5.5 m/s and the y component from v_iy = 3.8 m/s to V_fy = 3.0 m/s. If the ball has a mass of 0.45 kg and is in contact with the player's head for 7.1 ms, determine the following. direction of the impulse delivered to the ball _______ degree counterclockwise from the +x-axis magnitude of the impulse delivered to the ball _______ kg middot m/s

Explanation / Answer

5)

m = 0.135 Kg

u = 41 m/s

t = 1.15 ms

v = 45.9 m/s

average force acting on ball = magnitude of change in momentum/time

average force acting on ball = m * (v + u)/time

average force acting on ball = 0.135 * (41 + 45.9)/0.00115

average force acting on ball = 10201 N

6)

as the impulse is given as

Impulse = change in momentum

Impulse = m * (vf - vi)

Impulse = 0.45 * ((5.5 - 7.9)i + (3 - (-3.8))j )

Impulse = -1.08 i + 3.06 j Kg.m/s

dircetion of impulse = 180- arctan(3.06/1.08)

dircetion of impulse = 109.4 degree

the dircetion of impulse is 109.4 degree

b) magnitude of impulse = sqrt(1.08^2 + 3.06^2)

magnitude of impulse = 3.244 Kg.m/s

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