A baseball thrown from shoulder height with an initialvelocity of 29.4 m/s at an

Question

A baseball thrown from shoulder height with an initialvelocity of 29.4 m/s at an angle of 30.0o with respectto the horizontal. The ball is in its trajectory for a totalinterval of 3 seconds before being caught at shoulder height level(assume negligible air resistance). What is the balls horizontal displacement? EQUATION? A baseball thrown from shoulder height with an initialvelocity of 29.4 m/s at an angle of 30.0o with respectto the horizontal. The ball is in its trajectory for a totalinterval of 3 seconds before being caught at shoulder height level(assume negligible air resistance). What is the balls horizontal displacement? EQUATION? EQUATION?

Explanation / Answer

balls horizontal displacement   X = v ^ 2 sin2 / g where v = 29.4 m / s            = 30 degrees So, X = 76.38 m

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