A charge of 20 nC is uniformly distributed along a straightrod of length 4.0 m t

Question

A charge of 20 nC is uniformly distributed along a straightrod of length 4.0 m that is bent into a circular arc with a radiusof 2.0 m. What is the magnitude of the electric field at the centerof curvature of the arc? According to the solution, the central angle is114.6o. How did they find the angle just using radiusand length of the rod? A charge of 20 nC is uniformly distributed along a straightrod of length 4.0 m that is bent into a circular arc with a radiusof 2.0 m. What is the magnitude of the electric field at the centerof curvature of the arc? According to the solution, the central angle is114.6o. How did they find the angle just using radiusand length of the rod?

Explanation / Answer

central angle of an arc = the arc length/radius = 4.0/2.0 rad = 2rad = 2 * 180/ = 114.6o

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.