A charge of + 2.10 E -9 C is placed at the origin, and anothercharge of + 4.90 E

Question

A charge of + 2.10 E -9 C is placed at the origin, and anothercharge of + 4.90 E-9 C is placed at x = 1.7 m. The coulumb constantis 8.98755 E 9 N*m2 /C2 . Find thepoint (coordinate) between these two charges where a charge of +3.40 E-9 C should be placed so that the net electric force on it iszero? Answer in units of m. 1) I used this formula F = k q / r2 2) k ( + 2.10 E -9 C) / r2 = k (+4.90 E -9C)/ (1.7 m - r)2 To be honest i do not understand this question. I try tofollow a similar example done in class but it did not work. ifsomeone can help, I would really apreciated. Thank you A charge of + 2.10 E -9 C is placed at the origin, and anothercharge of + 4.90 E-9 C is placed at x = 1.7 m. The coulumb constantis 8.98755 E 9 N*m2 /C2 . Find thepoint (coordinate) between these two charges where a charge of +3.40 E-9 C should be placed so that the net electric force on it iszero? Answer in units of m. 1) I used this formula F = k q / r2 2) k ( + 2.10 E -9 C) / r2 = k (+4.90 E -9C)/ (1.7 m - r)2 To be honest i do not understand this question. I try tofollow a similar example done in class but it did not work. ifsomeone can help, I would really apreciated. Thank you To be honest i do not understand this question. I try tofollow a similar example done in class but it did not work. ifsomeone can help, I would really apreciated. Thank you

Explanation / Answer

let p be a point on x-axis at a distance d from the charge atorigin where the third charge should be placed the force between the charge at origin and the thirdcharge F1 = k * (q1 * q3/d^2) k = (1/4o) = 9 * 10^9 Nm^2/C^2 q1 = +2.10 * 10^-9 C q3 = +3.40 * 10^-9 C the force between the third charge and the second charge F2 = k * (q3 * q2/(1.7 - d)^2) the net electric force on the third charge is zerotherefore F1 + F2 = 0 or k * (q1 * q3/d^2) + k * (q3 * q2/(1.7 - d)^2) = 0 or k * (q1 * q3/d^2) = -k * (q3 * q2/(1.7 - d)^2) or (q1/d^2) = -(q2/(1.7 - d)^2) solving the above equation for d we get d = (1.7/1 - (q2/q1)^(1/2)) m

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