A single isolated, large conducting plate has a charge per unit area on its surf

Question

A single isolated, large conducting plate has a charge per unit area on its surface. Because the plate is a conductor, the electric field at its surface is perpendicular to the surface and has magnitude E = /Eo 5, The field from a large, uniformly charged sheet with charge per unit area has magnitude E = /2. why is there a difference? Regard the charge distribution on the conducting plate as two sheets of charge (one on each surface), each with charge per unit area . Find the electric field inside and outside the plate a. b.

Explanation / Answer

5. a) The conductor has the surface charge density on both sides,so it has twice the enclosed charge and twice the electricfield.

b) We have a conductor with surface charge density on bothsides. Thus the electric field outside the plateis is calculated by theformula  

                 = E(2A) = (2A)/0

                  then E = /0

To find the field inside the conductor, consider a Gaussian surface which has one face inside the conductor, and one outside.

Then = Eout A + Ein A = (A)/0

   But Eout = /0

Thus Ein = 0

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.