5.92 Block B, with mass Figure P5.92 5.00 kg, rests on block A, with mass 8.00 k

Question

5.92 Block B, with mass Figure P5.92 5.00 kg, rests on block A, with mass 8.00 kg, which in turn is on a horizontal tabletop (Fig. P5.92). There is no fric- tion between block A and the tabletop, but the coefficient of static friction between blocks A and B is 0.750. A light string attached to block A passes over a frictionless, massless pulley, and block C is suspended from the other end of the string. What is the largest mass that block C can have so that blocks A and B still slide together when the system is released from rest?

Explanation / Answer

here ,

for the blocks A and B to be together

the maximum accelerattion ,

8 * a = 0.750 * 5 * 10

a = 4.7 m/s^2

Now , Using second law of motion

a = (mC * g)/(mA + mB + mC)

4.7 = mC * 9.8/(5 + 8 + mC)

solving for mC

mC = 12 Kg

the mass of block C is 12 Kg

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