5.6 Systems and Energy Conservat Ag pole vaulter running at 10. m m/s vaults ove

Question

5.6 Systems and Energy Conservat Ag pole vaulter running at 10. m m/s vaults ove Hey speed when she is aove the bar is d to 5, (hild and a sled with a contined mass of 50 down a frictionless slope. If the sled starts from res resihtance, as well as any energy absorbed by determine her altitude as she crosses the bar and h ey" 1 33.0cm long spring is hung vertically from a cei retches to 41.5 cm when a 7.50kg weight is hung speed of 3.00 m/s at the bottom, what is the height Do S4. A 35.0cm free of the weight end. (a) Find the spring constant. (b) Find the l e spring if the 7.50-kg weight is replaced with a at 35. QCA0250-kg block along a horizontal track has a sp of 1.50 m/s immediately before colliding with a light sp of force constant 4.60 N/m located at the end of the tr ts (a) What is the spring's maximum compression if the track compression be greater than, less than, b VA block of mass m 5.00 kg is released from rest igure P5.36. Determine (a) the block's speed at points B and is frictionless? (b) If the track is not frictionless, would equal to the value ob (a)? from point and slides on the frictionless track shown in O and (b) the net work done by the gravitational force on the lock as it moves from point from ® to C. 5.00 m 3.20 m 2.00 m Figure P5.36 gle of 37.0 with the vertical. What is hi m of the swing (a) if he starts from rest th a speed of 4.00 m/s? ve nitially inclined at an s smped a Two blocks are connected by ctionless pulley as in

Explanation / Answer

a) From conservation of energy

m g (hA - hB) = 1/2 m vB2

vB = sqrt [2 g (hA - hB)] = sqrt [2 * 9.8 * (5.00 - 3.20)]

vB = 5.93 m/s

b) From conservation of energy

m g (hA - hC) = 1/2 m vC2

vC = sqrt [2 g (hA - hC)] = sqrt [2 * 9.8 * (5.00 - 2.00)]

vC = 7.66 m/s

c) W = m g (hA - hC)

= 5 * 9.8 * (5.00 - 2.00)

Work done = 147 J

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