A car travels along a straight line at a constant speed of 52.0 ml/h for a dista

Question

A car travels along a straight line at a constant speed of 52.0 ml/h for a distance of and then another distance of in the same direction at another constant speed. The average velocity for the entire trip is 33.0 ml/h. (a) What is the constant speed with which the car moved during the second distance d? Your response differs from the correct answer by more than 10%. Double check your calculation. ml/h (b) Suppose the second distance of were traveled in the opposite direction: you forgot something and had to return home at the same constant speed as found in part (a). What is the average velocity for this trip? ml/h (c) What is the average speed for this new trip? differs from the correct answer by more than 10%. Double check your calculation. ml/h

Explanation / Answer

from the given question,

Average speed(v)= total distance /total time

let the constant speed for second distnce(d)=u

total distance=d+d=2d

total time= d/52+ d/u

33= (2d)/[(d/52)+(d/u)]

33=(2)/[(1/52)+(1/u)]

solving we get u=24.17 mi/h

speed for the second distance is 24.17 mi/h

(b) Average velocity for new trip=(d-d)/[(d/52)+(d/24.17)]=0 mi/h

Average speed for new trip=(d+d)/[(d/52)+(d/24.17)]=33 mi/h

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