A car travelling at 10mph takes a corner of 10 yards radius. What is the acceler

Question

A car travelling at 10mph takes a corner of 10 yards radius. What is the acceleration of the car in ft/s2.

The formulas that I am given are as follows....  

           The first thing i did was convert the 10mph to 14.67 ft/s.  Then i found the angular velocity which is the w = v/r and got 0.498 rad/s but now im stuck.  I am nto sure what to do since i dont have the distance

     

      

Acceleration Formulas Rotational theta = theta0 + omega0t + 1/2 alphat2 omega = omega0 + alphat omega2 = omega +2 alphatheta v1 = romega s=rtheta a1 = rtheta an = v2/r or an = omega2r

Explanation / Answer

Velocity of car = 10 mph = 14.667 ft/sec

Radius of corner = 10 yards = 30 ft

Acceleration of car = v^2 / R

= 14.667^2 / 30

= 7.17 ft/sec^2

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