A solenoid of length 2.00 m and radius 1.00 cm carries a current 0.100 A. Determ

Question

A solenoid of length 2.00 m and radius 1.00 cm carries a current 0.100 A. Determine the magnitude of the magnetic field inside solenoid consists of 2000 turns of wire. The magnitude of the magnetic field at the center of a 25.0-cm-long s with 650.0 turns is 2.00 mT. What is current in the windings of the solenoid? You want to measure magnetic fields in the range between 10 mT and 100 mT using a compass. You cannot e the Earth's magnetic field as a reference because it is too weak. Instead, you will use a solenoid to create a uniform magnetic field. If you want to keep the current smaller than 2.0 A what is a reasonable value for the number of turns per unit length? A Solenoid in your car is 33 cm. It is made of copper wire with a radius of 0.51 mm. The turns are closely packed and form a single layer. Assume the resistivity of copper is 1.68 times 10^-8 Ohm middot m. a. When the solenoid is connected to your battery with epsilon = 11.6 V, what is the magnetic field inside the solenoid? b. If, instead, the turns form two layers, how does your answer change? The magnetic field inside a solenoid is 0.235 T. If the current is 4.53 A, how many turns are there per unit length? The magnetic field inside a diameter of solenoid is 23.7 cm long 0.235 T. If the current is 4.53 and the diameter of the solenoid is 2.37 cm, what are the total number of turns and the length of the wire? A square conducting loop with side length a = 1.25 cm placed at the center of a solenoid 40.0 cm long with 300 turns and aligned so that the plane of the loop perpendicular to the long axis of the solenoid. According to an observer, the current in the single turn of the loop is 0.800 A in the counterclockwise direction, and the current in the windings of the solenoid

Explanation / Answer

we know that, magnetic field of solenoid,

B = uo n i

= 4pi*10^-7*(2000/2)*0.1

= 0.000126 T. Answer

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